查看单个帖子
旧 2009-09-16, 12:32 AM   #1
huangyhg
超级版主
 
huangyhg的头像
 
注册日期: 04-03
帖子: 18592
精华: 36
现金: 249466 标准币
资产: 1080358888 标准币
huangyhg 向着好的方向发展
默认 solving for impact loading

solving for impact loading
i am doing an overhead steel beam that will have a fall arrest system that will run along the bottom flange of the beam. how do you determine the actual force? up here in canada we used to have a factor of 1.65 for loading lasting less than 10 min. this is a project for the us.
basically, if a 200 lbs man fell what would the force be? would it be as simple as f=ma? or is there a factor to use?
thanks
check out our whitepaper library.
i believe we typically use a load of 1.5 kips in any direction. you can lower it if you meet certain criteria, but that is a good starting point.
__________________
借用达朗贝尔的名言:前进吧,你会得到信心!
[url="http://www.dimcax.com"]几何尺寸与公差标准[/url]
huangyhg离线中   回复时引用此帖
GDT自动化论坛(仅游客可见)