solving for impact loading
 

solving for impact loading
i am doing an overhead steel beam that will have a fall arrest system that will run along the bottom flange of the beam. how do you determine the actual force? up here in canada we used to have a factor of 1.65 for loading lasting less than 10 min. this is a project for the us.
basically, if a 200 lbs man fell what would the force be? would it be as simple as f=ma? or is there a factor to use?
thanks
check out our whitepaper library.
i believe we typically use a load of 1.5 kips in any direction. you can lower it if you meet certain criteria, but that is a good starting point.