几何尺寸与公差论坛

 找回密码
 注册
查看: 525|回复: 0

ultimate strength = norminal strength

[复制链接]
发表于 2009-9-16 16:53:55 | 显示全部楼层 |阅读模式
ultimate strength = norminal strength ?
in concrete structure member design, is the ultimate srtength equal to the norminal strength or the norminal strength times the strength reduction factor (phi)? for example, ultimate p = pn or (phi)*pn? ultimate m = mn or (phi)*pn? thank you very much.

the ultimate strength is the unfactored value.
applied load must be less than available strength.
applied load
you apply loads to a structure and get an effect....say an axial load, p.
you mulitiply this load times a load factor to get a factored (ultimate) load, pu  (i.e. pu = 1.6 x p)
available strength
you calculate the capacity of your member based upon derived formulae which are based upon tests, concepts, etc. to get pn, which is the nominal strength of the member.
you multiply the nominal strength of the member times a strength reduction factor φ(to account for variabilities in calculating the strength accurately) and this gives you the member design capacity φpn.
compare
in strength design, therefore, you choose, size, or specify a member big enough so that:
pu <= φpn
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|Archiver|小黑屋|几何尺寸与公差论坛

GMT+8, 2025-5-1 23:02 , Processed in 0.036204 second(s), 19 queries .

Powered by Discuz! X3.4 Licensed

© 2001-2023 Discuz! Team.

快速回复 返回顶部 返回列表